Question

How many moles of NH3 are produced when 0.60 mol of nitrogen reacts with hydrogen in N2 + 3H2 ----> 2NH3

Answer 1

0.80 mol

Step-by-step explanation:

n(H)/n(N) = 1/3

n(N) = 3×0.60

n(N) = 1.8 mol

n(N) in excess = 1.80-0.60 = 1.20 mol

n(N)/n(NH3) = 3/2

n(NH3) = 2/3×1.20 = 0.80 mol