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If the point (2k− 3,k + 2) is a solution of linear equation 2x + 3y + 15 = 0, find the value of k.
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If the point (2k− 3,k + 2) is a solution of linear equation 2x + 3y + 15 = 0, find the value of k.

User Rango
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2 Answers

9 votes
2k - 3 ——> x-coordinate
k + 3 ——> y-coordinate


2x + 3y + 15 = 0

Sub (2k-3 , k+2) into the equation,

2(2k - 3) + 3(k + 2) + 15 = 0

4k - 6 + 3k + 6 + 15 = 0

4k + 3k = 0 - 15 - 6 + 6

7k = -15

k = -15/7
User Eran Peled
by
4.3k points
4 votes

Answer:

value of k = -15/7

Explanation:

...........

If the point (2k− 3,k + 2) is a solution of linear equation 2x + 3y + 15 = 0, find-example-1
User Chantastic
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