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If the point (2k− 3,k + 2) is a solution of linear equation 2x + 3y + 15 = 0, find the value of k.
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Apr 11, 2022
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If the point (2k− 3,k + 2) is a solution of linear equation 2x + 3y + 15 = 0, find the value of k.
Mathematics
high-school
Rango
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2k - 3 ——> x-coordinate
k + 3 ——> y-coordinate
2x + 3y + 15 = 0
Sub (2k-3 , k+2) into the equation,
2(2k - 3) + 3(k + 2) + 15 = 0
4k - 6 + 3k + 6 + 15 = 0
4k + 3k = 0 - 15 - 6 + 6
7k = -15
k = -15/7
Eran Peled
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Apr 13, 2022
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Answer:
value of k = -15/7
Explanation:
...........
Chantastic
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Apr 16, 2022
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