Question

8) A force of 10 N stretches a spring 0.50 m from equilibrium. What is the value of the spring constant?​

Answer 1

Step-by-step explanation:

We use Hooke's Law, which states that,

F=kx

F- is the force in newtons

k- is the spring constant

x- is the extension of the spring in meters

Solving for k we get k=F/x

k= 10N/0.50m

=100 N/m