Question

X (27-x) = 182
Please help me by solving this!​

Answer 1

We are provided with a expression as follows ;

• 
  `{\sf x(27-x)=182}`

Can be further written as ;

`{: \implies \quad \sf 27x-{x^(2)}=182}`

`{: \implies \quad \sf {x^2} -27x + 182=0}`

Using splitting the middle term we have ;

`{: \implies \quad \sf {x^2} - 13x-14x+182=0}`

`{: \implies \quad \sf x(x-13)-14(x-13)=0}`

`{: \implies \quad \sf (x-13)(x-14)=0}`

Case I :-

When , (x-13)=0 , then clearly x = 13

Case II :-

When , (x-14)=0 , then clearly x = 14

Hence , The required values of x are 13 and 14 respectively