Question

The size of a TV is determined by the length of the diagonal of the TV. A 42" TV means the length from one corner to the other is 42 inches. If the diagonal forms a 30 degree angle with the base of the TV, what are the height and width of the TV? *

Answer 1

length = 5.38 feet

Explanation:

All the eq. can be solved by Phythagoras's theorem

1) Diagonal is 70 inches, height is 42 inches so

70^2 = 42^2 + width^2

width ^2 = 3136, width = 56 inches

2) Base is 2 ft, length of ladder = hypotenuse = 10 ft

Height^2 = 10^2 -2^2 = 96

Height = 9.8 ft

3) Equilateral triangle has a side of 6

If you drop a vertical line from one corner of triangle to opposite side it bisects the side into equal parts. So the length of base is 3

The hypotenuse is 6

So height is sqrt (6*6 -3*3) = sqrt (27) = 3sqrt(3) = 5.2

4) Height = 12, width = 5

Diagonal^2 = 12*12 + 5*5 = 169

Diagonal = 13

5) Plant is 5 ft tall, distance from the ground is 2 ft

length ^2 = 5*5 + 2*2 = 29

length = 5.38 feet