y-yi=m(x-xi)
y-3=1/4(x-4)
y-3=x-4/4
4y-12=x-4
4y+x-12+4=0
4y+x-8=0
so the equation of
the line perpendicular
to
y=1/4-5 through
the point(4,3)
is4y-x-8=0
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