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Please help me with both please

Please help me with both please-example-1
User Teo
by
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1 Answer

9 votes

Answer:

1. 3ft
2. 70.529°

Explanation:
Question 1:

Calculated based on 2 given angles and 1 given side.

∠A = 180° - B - C = 0.5236 rad = π/6 = 30°

a = b·sin(A)/sin(B) = 3.4641 = 2
√(3)

c = b·sin(C)/sin(B) = 6.9282 = 4
√(3)

Area =
(ab·sin(C))/(2) = 10.3923

Perimeter p = a + b + c = 16.3923

Semiperimeter s =
(a + b +c)/(2) = 8.19615

Height hα =
(2×Area)/(a) = 6

Height hb =
(2×Area)/(b) = 3.4641

Height hc =
(2×Area)/(c) = 3

Median ma =
√((a/2)2 + c2 - ac·cos(B)) = 6.245

Median mb =
√((b/2)2 + a2 - ab·cos(C)) = 4.58258

Median mc =
√((c/2)2 + b2 - bc·cos(A)) = 3.4641

Inradius r =
(Area)/(s) = 1.26795

Circumradius R =
(a)/(2sin(A)) = 3.4641


Question 2:
Calculates b, ∠A, and ∠B based on given c, a, and ∠C.

∠A = arcsin(
(a·sin(C))/(c)) = 0.33984 rad = 19.471° = 19°28'16"

∠B = 180° - C - A = 1.23096 rad = 70.529° = 70°31'44"

b =
(c·sin(B))/(sin(C)\\) = 11.31371 = 8√2

Area =
(ab·sin(C))/(2) = 22.62742

Perimeter p = a + b + c = 27.31371

Semiperimeter s =
(a + b +c)/(2) = 13.65685

Height hα =
(2×Area)/(a) = 11.31371

Height hb =
(2×Area)/(b) = 4

Height hc =
(2×Area)/(c) = 3.77124

Median ma =
√((a/2)2 + c2 - ac·cos(B) )= 11.48913

Median mb =
√((b/2)2 + a2 - ab·cos(C)) = 6.9282

Median mc =
√(√(c/2)2 + b2 - bc·cos(A)) = 6

Inradius r =
(Area)/(s) = 1.65685

Circumradius R =
(a)/(2sin(A)) = 6

User Tuanngocptn
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