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A particular population of chickens has a frequency for the dominant allele as 0.70 and a frequency for the recessive allele as 0.30. Which expression is the correct way to calculate the frequency of individuals that are heterozygous?

A.
(0.70) × (0.30)
B.
(0.70) – (0.30)
C.
2 × (0.70) × (0.30)
D.
2 × (0.70 – 0.30)

1 Answer

10 votes

Answer:

C.) 2 x(0.70) x (0.30)

Step-by-step explanation:

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