Question

Example 1 How much water (in grams) is produced when 65.2 grams of Calcium carbonate react with phosphoric acid to form calcium phosphate, water, and carbon dioxide?​

Answer 1

11.75 g H2O

Step-by-step explanation:

3CaCO3 + 2H3PO4 --> Ca3(PO4)2 + 3H2O + 3CO2

MM H2O = 18.02 g/mol

MM CaCO3 = 100 g/mol

? g H2O = mass CaCO3 x (1 mol CaCO3/MM CaCO3) x (3 moles H2O/3 moles CaCO3) x (MM H2O / 1 mol H2O) = (65.2/100) x 18.02 = 11.75 g H2O