Question

56 is less than the square of 10 ​

Answer 1

Let X be the positive number.

From the given condition, we get X = X^2–56

=> X^2-X-56=0

Factorizing the above equation,

=> X^2–8X+7X-56=0

X(X-8)+7(X-8)=0

(X-8)(X+7)=0

X=8 or -7

Since it is said the number is positive. Our output number will be 7