Question

Write a sine function that has a midline of 5, an amplitude of 4 and a period of 7/5

Answer 1

`y=4sin((10\pi)/(7)x)+5`

Explanation:

Recall formula

`y=asin(bx+c)+d\\\\y=4sin(bx)+5`

Determine b from period

`(2\pi)/(b)=(7)/(5)\\ \\ 10\pi=7b\\\\b=(10\pi)/(7)`

Final Equation

`y=4sin((10\pi)/(7)x)+5`