Write a sine function that has a midline of 5, an amplitude of 4 and a period of 7/5

asked Mar 3, 2023 84.6k views

12 votes

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2 votes

Answer:

$y=4sin((10\pi)/(7)x)+5$

Explanation:

Recall formula

$y=asin(bx+c)+d\\\\y=4sin(bx)+5$

Determine b from period

$(2\pi)/(b)=(7)/(5)\\ \\ 10\pi=7b\\\\b=(10\pi)/(7)$

Final Equation

$y=4sin((10\pi)/(7)x)+5$

Tersosauros answered Mar 10, 2023

3.2k points

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