Question

The locus B on the X chromosome of a malaria-carrying mosquito shows a 49% recombination rate with respect to the locus M. Since a recombination rate of 50% is essentially indistinguishable from independent assortment, you might be tempted to look for a locus that falls between B and M. Before you decide to do all that work, you run a chi square test to determine the P value of your experiment.

Required:
What range of P values would tell you that you should accept the conclusion that locus B and locus M are, indeed, 49mu apart and that another locus is not necessary?

Answer 1

The correct answer is - P = 0.45

Step-by-step explanation:

The Chi-square test is a test that determines the assorted genes independently. Here p-values used to make conclusions in significance testing.

If the p value is less than the significance level we expect or choose, then this null hypothesis is rejected in favor of the alternative hypothesis. It p value is greater than or equal to the significance level, then we fail to reject the null hypothesis.

So in this case, as the recombination rate is 49% so the p value which satisfies the conclusion will be around 0.45 and values near to it.