Answer:
113.17 g
Step-by-step explanation:
This can be solved using the Ideal Gas Equation:
PV=nRT
First step is to calculate the volume of the cylinder in L:
V=πr²h
V= π (11.5)² (140)
V= π (132.25) (140)
V = π (18.515)
V = 58,166.588 cm³ = 58.2 L
Then, convert kpa into atm:
1 kpa = 0.00987 atm
108 kpa = 1.06588 atm
Then, plug all of your values into the Ideal Gas Equation to solve for moles:
(1.06588)(58.2)=n(0.082057)(294)
62.034=n(24.125)
2.571357513=n
Finally, convert the moles into grams
2N = 28.0134 amu
O = 15.999 amu
_______________
44.0124 amu
(2.571357513moles)(44.0124 amu) = 113.17 g