155k views
23 votes
A 5.0 kg bowling ball is sitting on a rack and its gravitational potential energy is 74 J. How high is the bowling ball above the floor? GIVE WORK

2 Answers

6 votes


\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Work, energy and power.

Potential energy = m*g*h, here g = 9.8 m/s^2 (universal value)

hence, h = P/m*g

==> h = 74/ 5*9.8

===> h = 74/49

==> h = 1.51 meters

hence the height is 1.51 m

User Silvio Mayolo
by
5.0k points
4 votes

Answer:

1.48m

Step-by-step explanation:

mgh=Wp

h=Wp/mg

h=74J/50N

h=1.48m

User Vedat
by
5.0k points