Given:
The figure of a right angle triangle.
To find:
The value of x and measures of all angles of the triangle.
Solution:
According to the angle sum property, the sum of all interior angles of a triangle is 180 degrees.
Using angle sum property, we get
![(x+60)^\circ+(x+50)^\circ+90^\circ=180^\circ](https://img.qammunity.org/2022/formulas/mathematics/high-school/z7lxjtggv57hejleowiwsr3qousms8gmgz.png)
![(2x+200)^\circ=180^\circ](https://img.qammunity.org/2022/formulas/mathematics/high-school/r14py39m3rl8zm0ego4bc0cpfx21wsd9k6.png)
![(2x)^\circ=180^\circ-200^\circ](https://img.qammunity.org/2022/formulas/mathematics/high-school/ens6tz4kfabliiimnicn0jcqxb9spslifg.png)
![(2x)^\circ=-20^\circ](https://img.qammunity.org/2022/formulas/mathematics/high-school/943bz8qyvk8wcl408cdxvtp70qgky7wqt1.png)
It can be written as
![(2x)=-20](https://img.qammunity.org/2022/formulas/mathematics/high-school/x9agmrk139ucsc6l63bfv2j1pl16dx3qwx.png)
Divide both sides by 2.
![x=-10](https://img.qammunity.org/2022/formulas/mathematics/high-school/giijzmydgovdnckpu97n74fyne4bpsx9v1.png)
The value of x is -10.
Now,
![m\angle A=x+50](https://img.qammunity.org/2022/formulas/mathematics/high-school/2fa0m5x0as8747hdp4xrrs1w5zneiir47w.png)
![m\angle A=-10+50](https://img.qammunity.org/2022/formulas/mathematics/high-school/d3viesovjfse8frr8xpdri0wuhppaa3una.png)
![m\angle A=40](https://img.qammunity.org/2022/formulas/mathematics/high-school/kjfvhog65utfwe3qd1u44riozdgm7dbfjb.png)
And,
![m\angle B=x+60](https://img.qammunity.org/2022/formulas/mathematics/high-school/y2y6x26m2vx39jw5pez7vafk7l8y48o2cu.png)
![m\angle B=-10+60](https://img.qammunity.org/2022/formulas/mathematics/high-school/124kgciq171wd729zkfem2a38eehty9rhw.png)
![m\angle B=50](https://img.qammunity.org/2022/formulas/mathematics/high-school/7v30qdhfejyq3916pql1hhcvaevgt8r6mr.png)
Therefore, the value of x is -10, measure of angle A is 40 degrees and measure of angle B is 50 degrees.