Question

Find the margin of error for a 95% confidence interval for μ; n=49,σ = 4.8 Keep all decimal places.

Answer 1

1.344

Explanation:

Given that:

n=49,σ = 4.8

Zcritical = 95%

Using the relation :

Margin of Error = Zcritical * sqrt(σ² / n)

Zcritical at 95% = 1.96

Margin of Error = 1.96 * sqrt(4.8² / 49)

Margin of Error = 1.96 * (4.8 / 7)

Margin of Error = 1.96 * 0.6857142

Margin of Error = 1.344