Question

Which is the equation of the line that passes through the points (4,3) and (6,2)

Answer 1

y = -1/2x + 5

Explanation:

Find slope:

change in y/change in x

(2-3)/(6-4)

-1/2 = m

Use point-slope form:

y - y1 = m(x - x1)

Where (x1, y1) is a point on the line, let's use (4,3)

y - 3 = -1/2(x - 4)

Point-intercept form:

Expand y - 3 = -1/2(x - 4) to get point-slope form:

y = -1/2x + 5

Hope this helps!! :)