Answer:
(√366 - 3)/24
Explanation:
Given the following:
cos∝ = √3/8 and sinβ = √3/3
Sin(∝-β) = sin∝cosβ - cos∝sinβ
Get sin∝
Since cos∝ = √3/8
adj = √3
hyp = 8
opp = √8² - (√3)²
opp = √64 - 3
opp = √61
Recall that sin∝ = opp/hyp
sin∝ = √61/8
Get cosβ
Since sinβ = √3/3
opp = √3
hyp = 3
adj =√3² - (√3)²
adj = √9-3
adj = √6
Recall that cosβ = adj/hyp
cosβ = √6/3
Substitute the gotten values into the formula
Sin(∝-β) = sin∝cosβ - cos∝sinβ
Sin(∝-β) = ( √61/8)(√6/3)- (√3/8)(√3/3)
Sin(∝-β) = √366/24 - √9/24
Sin(∝-β) = (√366 - 3)/24