Question

What will be the change in velocity of a 850 kg car if a force of 50,000N is

applied for 0.5 s? (Round to one decimal)

Answer 1

29.4 m/s

Step-by-step explanation:

f = ma

a =
`(f)/(m)`

a =
`(50000)/(850)`

a = 58.8
`m/s^(2)`

a =
`(change in velocity)/(t)`

change in velocity= at

change in velocity = 58.8 × 0.5

change in velocity = 29.4 m/s

Answer 2

i'm not quite sure

Step-by-step explanation:

just grive me a sec