Factor the Quadratic: 3x^2+12x-36=0

Michael De Silva asked May 12, 2022

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Michael De Silva asked May 12, 2022

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20 votes

Answer:

3x ^ 2 + 12x-36 = 0

3(x²+ 4x-12)=0

3(x²-2x+6x-12)=0

3[x(x-2)+6(x-2)]=0

3(x-2)(x+6)=0

⇒
$\left \{ {{x-2=0} \atop {x+6=0}} \right.$ ⇔
$\left \{ {{x=2} \atop {x=-6}} \right.$

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