Register
1^2 + 4^2 + 7^2 -... - (3n - 2)^2 = n(6n^2 - 3n - 1)/2
157k views
12 votes
1^2 + 4^2 + 7^2 -... - (3n - 2)^2 = n(6n^2 - 3n - 1)/2

User Nadeem Qasmi
by
3.2k points

1 Answer

2 votes

Answer:

1

2

+

4

2

+

7

2

−

.

.

.

−

(

3

−

2

)

2

=

(

6

2

−

3

−

1

)

/

2

Explanation:

User Neeraj Joshi
by
4.0k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

3.6m questions

4.5m answers

Other Questions

A study was completed in Florida. In southern Florida, the study involved 3,000 patients; 54% of them experienced flulike symptoms during the same month. The study had a margin of error of 1.8%. What does
Solve for x in the equation 3 x squared minus 18 x + 5 = 47. (I need this to be an answer like X=3+\_ square root 23)
Can someone help me plz I have to Turn 27/9 in simplest
The sanchez family goes out for dinner, and the price of the meals is $60. The sales tax on the Meals is 7 percent, and they also want to leave a 15 percent tip. What is the total cost of the meal? Analyze
Simplify: 10 ÷ [(5 + 2) − 5]
Link Copied!