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1^2 + 4^2 + 7^2 -... - (3n - 2)^2 = n(6n^2 - 3n - 1)/2
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1^2 + 4^2 + 7^2 -... - (3n - 2)^2 = n(6n^2 - 3n - 1)/2

User Nadeem Qasmi
by
4.6k points

1 Answer

2 votes

Answer:

1

2

+

4

2

+

7

2

−

.

.

.

−

(

3

−

2

)

2

=

(

6

2

−

3

−

1

)

/

2

Explanation:

User Neeraj Joshi
by
5.5k points
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