89.1k views
1 vote
what is the common ratio of a geometric progression were the first term is 3 and the 4th term is 648​

User Noam Ross
by
3.1k points

1 Answer

7 votes

Answer:


r = 6

Explanation:

Given


a = 3 --- First, term


T_4 = 648 --- Fourth term

Required: Determine the common ratio

The nth term of a GP is


T_n = ar^{n-1

Substitute 4 for n


T_4 = ar^{4-1


T_4 = ar^{3

Substitute 648 and 3 for T4 and 3 respectively.


648 = 3 * r^{3


r^3 = 216

Take cube roots of both sides


r =\sqrt[3]{216}


r = 6

The common ratio is 6

User Shaphan
by
4.0k points