Question

What is the y-intercept of the equation of the line that is perpendicular to the line and passes through the point (15,-5)?

Answer 1

10

Explanation:

First of all let’s find out the slope of the line y = x +10

As, we know the equation y= mx + c . So comparing the given equation with the general equation we get, m = 1

Now, we know that the product of two perpendicular lines is -1.

Thus, mn = -1 (considering slope of the second line as n)

Putting the value of m we get , n = -1

Now , y+5= -1( x -15) i.e y=-x + 10

if we compare again with the general equation then we find that.

The y intercept of the required equation is 10.

Thank You

Answer 2

hi

Explanation:

First of all let’s find out the slope of the line y = x +10

As, we know the equation y= mx + c . So comparing the given equation with the general equation we get, m = 1

Now, we know that the product of two perpendicular lines is -1.

Thus, mn = -1 (considering slope of the second line as n)

Putting the value of m we get , n = -1

Now , y+5= -1( x -15) i.e y=-x + 10

if we compare again with the general equation then we find that.

The y intercept of the required equation is 10.

Thank You