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27n⁵+75n³ (Factor completely)

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27n⁵+75n³ (Factor completely)

asked Oct 28, 2022 228k views

1 vote

27n⁵+75n³ (Factor completely)

Mathematics
high-school

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2 Answers

9 votes

$\tt{}27n^(5) + 75 {n}^(3)$

$\tt{} {3n}^(2) * (9 {n}^(2) + 25)$

Mealesbia answered Oct 30, 2022

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11 votes

Answer:

3n^2 (9+25n)

Explanation:

Rand Scullard answered Nov 1, 2022

by Rand Scullard

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