Answer:
Pentagon = 72°
Octagon = 45°
Explanation:
To solve for the measure of one exterior angle in a regular pentagon;
n = number of sides
180 - (180 x n-2/n)
180 - (180 x 5-2/5)
180 - (180 x 3/5)
180 - (540/5)
180 - 108
Exterior angle = 72°
To solve for the measure of one exterior angle in a regular octagon;
n = number of sides
180 - (180 x n-2/n)
180 - (180 x 8-2/8)
180 - (180 x 6/8)
180 - (1080/8)
180 - 135
Exterior angle = 45°