Answer:
(3c−2d)(2a+b)
Explanation:
3bc−4ad+6ac−2bd
Do the grouping 3bc−4ad+6ac−2bd=(6ac−4ad)+(3bc−2bd), and factor out 2a in the first and b in the second group.
2a(3c−2d)+b(3c−2d)
Factor out common term 3c−2d by using distributive property.
(3c−2d)(2a+b)