Question

If the mass of the object doubles then the acceleration is when the force is kept the same

Answer 1

Halved

Step-by-step explanation:

F=ma

Let case 1 (original) be:

`F_(1)=m_(1) a_(1) \\`

Case 2 (new) be:

`F_(2)=m_(2) a_(2)`

Mass is double:

`m_(2)= 2m_(1)`

Force kept the same:

`F_(1) =F_(2)`

Combine the equation and gives:

`(F_(1) )/(F_(2)) =(m_(1) a_(1) )/(m_(2)a_(2) )\\(F_(1) )/(F_(1)) =(m_(1) a_(1) )/(2m_(1)a_(2) )\\1=(a_(1) )/(2a_(2) )\\a_(2)=(1)/(2) a_(1)`

Acceleration is halved