Answer:
the process capability index of the machine is 2.5
Option c) [More than 2 but less than or equal to 3] is the correct answer
Explanation:
Given the data in the question;
process average ( x') = 12.000 ounces
standard deviation σ = 0.002 ounces
the design specification for the fill weight of the bottles is 12.000 ounces plus or minus 0.015 ounces.
so
Upper specification Limit USL = 12.000 + 0.015 = 12.015 ounces
Lower specification Limit LSL = 12.000 - 0.015 = 11.985 ounces
the process capability index of the machine will be;
Cp = ( process average - Lower specification Limit ) / 3σ
so we substitute
Cp = ( 12 - 11.985 ) / ( 3 × 0.002 )
Cp = 0.015 / 0.006
Cp = 2.5
Therefore, the process capability index of the machine is 2.5
Option c) [More than 2 but less than or equal to 3] is the correct answer