Question

CosA/1-sinA=1+sinA/cosA​

Answer 1

see explanation

Explanation:

Using the trigonometric identity

sin²x + cos²x = 1 ⇒ cos²x = 1 - sin²x

Consider the left side

`(cosA)/(1-sinA)` ← multiply numerator/denominator by (1 + sinA)

=
`(cosA(1+sinA))/((1-sinA)(1+sinA))` ← expand denominator using FOIL

=
`(cosA(1+sinA))/(1-sin^2A)`

=
`(cosA(1+sinA))/(cos^2A)` ← cancel cosA on numerator/ denominator

=
`(1+sinA)/(cosA)`

= right side , thus proven