Answer:
31.96°C
Step-by-step explanation:
Given that,
Mass of water, m = 100 g
Initial temperature,
![T_i=20^(\circ) C](https://img.qammunity.org/2022/formulas/physics/high-school/leoqcqqlpwk9bny9f0eiomjwygjuzwfyjw.png)
The specific heat capacity of water is 4.18 J/(g℃)
We need to find the final temperature of the water if 5000. J of energy is added to the water in the insulated cup.
The heat added to the water is given by :
![Q=mc\Delta T\\\\Q=mc(T_f-T_i)\\\\(Q)/(mc)+T_i=T_f\\\\T_f=(5000)/(100* 4.18)+20\\\\T_f=31.96^(\circ) C](https://img.qammunity.org/2022/formulas/chemistry/high-school/gr6s75gptmkvrbx4lvkx08mp75uk79sz7p.png)
So, the final temperature is 31.96°C.