Answer:
1.
![3 : 2 = H : C](https://img.qammunity.org/2022/formulas/mathematics/high-school/tokog9ahgv1tev0n1gp2fshgexubvlkkzb.png)
2.
![2 : 3 = C : H](https://img.qammunity.org/2022/formulas/mathematics/high-school/bth32uyx3ckt0punxz9hq4yb50o17gyoc7.png)
3.
![2 : 2 = O : T](https://img.qammunity.org/2022/formulas/mathematics/high-school/gi3ifb57x6pro88rrjwref32fe8eh9b3sh.png)
4.
![13 : 3 = All\ Letters : H](https://img.qammunity.org/2022/formulas/mathematics/high-school/otyddwqvd6uq3mxi106id2m6r13a1bel3j.png)
5.
![2 : 13 = E : All\ Letters](https://img.qammunity.org/2022/formulas/mathematics/high-school/wrl0860afq6l7gxx16dxrpfwyxelsz0yxj.png)
Explanation:
See comment for complete question.
We have the following letters and their frequencies
![E = 2](https://img.qammunity.org/2022/formulas/chemistry/high-school/m3fwgaz1hvskyyirieunl0smn9eimgppy3.png)
Solving (1): 1.
![3 : 2 = H : [\ ]](https://img.qammunity.org/2022/formulas/mathematics/high-school/x0fj9rl9xiuou7w009vvmxonkmtmp0uzv7.png)
From the alphabets listed above:
,
![E = 2](https://img.qammunity.org/2022/formulas/chemistry/high-school/m3fwgaz1hvskyyirieunl0smn9eimgppy3.png)
So, the 3:2 can be H : any of the alphabets. For this solution, we use:
![3 : 2 = H : C](https://img.qammunity.org/2022/formulas/mathematics/high-school/tokog9ahgv1tev0n1gp2fshgexubvlkkzb.png)
Solving (2)
![2 : 3 = [\ ] : H](https://img.qammunity.org/2022/formulas/mathematics/high-school/g009bkw4xsb05lsrjnzcyda0qffsy3j0xg.png)
This is the inverse of (1) solved above.
So 2 : 3 is:
![2 : 3 = C : H](https://img.qammunity.org/2022/formulas/mathematics/high-school/bth32uyx3ckt0punxz9hq4yb50o17gyoc7.png)
Solving (3)
![2 : 2 = O : [\ ]](https://img.qammunity.org/2022/formulas/mathematics/high-school/yybno86zb11l2tpef7jvxbemtbwx4285kb.png)
From the alphabets listed above:
![E = 2](https://img.qammunity.org/2022/formulas/chemistry/high-school/m3fwgaz1hvskyyirieunl0smn9eimgppy3.png)
Any selected alphabet will represent 2 : 2
So, we have:
or O : any of C, A and E
Solving (4):.
![13 : 3 = [\ ] : H](https://img.qammunity.org/2022/formulas/mathematics/high-school/scy7ii8rt9l1jgt9wl5im1loc0n87kxb2m.png)
The total of all alphabet in the given word is: 13.
So,
![13 : 3 = All\ Letters : H](https://img.qammunity.org/2022/formulas/mathematics/high-school/otyddwqvd6uq3mxi106id2m6r13a1bel3j.png)
Solving (5):
![2 : 13 = E : [\ ]](https://img.qammunity.org/2022/formulas/mathematics/high-school/eawxinvjqr34d2fd8urvdmwd179rfxokbs.png)
The total of all alphabet in the given word is: 13.
So,
![2 : 13 = E : All\ Letters](https://img.qammunity.org/2022/formulas/mathematics/high-school/wrl0860afq6l7gxx16dxrpfwyxelsz0yxj.png)