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PLEASE HELP ME ON 6-11 AND SHOW WORK PLEASE!!

PLEASE HELP ME ON 6-11 AND SHOW WORK PLEASE!!-example-1
User King Julien
by
2.7k points

2 Answers

18 votes
18 votes

Answer:

6) 6
√(2)

9) 40

10)
(5√(2) )/(2)

11) 13

Explanation:

6)A right triangle rule: if 2 legs are equal, the hypotenuse is the length of that leg*
√(2)

9) Pythagorean Theorem


a^(2) +b^(2) =c^(2)

We know the hypotenuse (41) so we substitute that for c and 9 for b now we need to find a


\sqrt{41^(2)-9^(2) } which gives us 40

10) same with #6 but we do the opposite. SInce we have the hypotenuse, we can divide that by
√(2) because we know that if 2 legs are equal, the hypotenuse is multiplied by
√(2). Multiply the numerator and denominator by
√(2) because we can't have a square root in the denominator.

11) like #9 we have the a and b but we need to find c

a=5 b=12 c=r

so
\sqrt{5^(2)+12^(2) } which gives us 13

User Catlin
by
3.3k points
20 votes
20 votes

QUESTION:- FIND THE VARIABLES


\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}

6TH PART ->

GIVEN

  1. RIGHT ANGLE SO ITS A RIGHT ANGLED TRIANGLE SO WE CAN USE PYTHAGOUS THEOREM
  2. TWO SIDES ( BASE AND PERPENDICULAR) R EQUAL TO 6

SOLUTION->


{h}^(2) = {p}^(2) + {b}^(2)


{c}^(2) = {6}^(2) + {6}^(2) \\ {c}^(2) = 36 + 36 \\ c = \sqrt{2( {6}^(2) )} \\ c = √(2){\sqrt{ {6}^{{2}} } } \\ c = 6 √(2) \: \: \: ans

9TH PART:-

GIVEN

  1. RIGHT ANGLE SO ITS A RIGHT ANGLED TRIANGLE SO WE CAN USE PYTHAGOUS THEOREM
  2. BASE = 9
  3. HYPOTENUSE= 41

SOLUTION->


{h}^(2) = {p}^(2) + {b}^(2)


{41}^(2) = {x}^(2) + {9}^(2) \\ 1681 = {x}^(2) + 81 \\ 1681 - 81 = {x}^(2) \\ 1600 = {x}^(2) \\ x = √(40 * 40) \\ x = 40 \: \: \: ans

10 TH PART:-

GIVEN

  1. RIGHT ANGLE SO ITS A RIGHT ANGLED TRIANGLE SO WE CAN USE PYTHAGOUS THEOREM
  2. TWO SIDES ( BASE AND PERPENDICULAR) R EQUAL TO S
  3. HYPOTENUSE= 5

SOLUTION->


{h}^(2) = {p}^(2) + {b}^(2)


{5}^(2) = {s}^(2) + {s}^(2) \\ 25 = 2 {s}^(2) \\ 12.5 = {s}^(2) \\ √(12.5) = s \\ 3.5 = s \: \: \: ans

11TH PART:-

GIVEN

  1. RIGHT ANGLE SO ITS A RIGHT ANGLED TRIANGLE SO WE CAN USE PYTHAGOUS THEOREM
  2. BASE = 5
  3. PERPENDICULAR= 12

SOLUTION ->


{h}^(2) = {p}^(2) + {b}^(2)


{r}^(2) = {12}^(2) + {5}^(2) \\ {r}^(2) \\ 144 + 25 \\ {r}^(2) = 169 \\ r = √(13 * 13) \\ r = 13 \: \: \: \: ans

HOPE IT HELPED


\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \star \: DEVIL005 \: \star

User Mohd Sakib Syed
by
3.4k points