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Urgent please help me

Urgent please help me-example-1
User Chemic
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1 Answer

16 votes
16 votes

1433 km

Step-by-step explanation:

Let g' = the gravitational field strength at an altitude h


g' = G(M_E)/((R_E + h)^2)

We also know that g at the earth's surface is


g = G(M_E)/(R_E^2)

Since g' = (2/3)g, we can write


G(M_E)/((R_E + h)^2) = (2)/(3)\left(G(M_E)/(R_E^2) \right)

Simplifying the above expression by cancelling out common factors, we get


(R_E + h)^2 = (3)/(2) R_E^2

Taking the square root of both sides, this becomes


R_E + h = \left(\!\sqrt{(3)/(2)}\right) R_E

Solving for h, we get


h = \left(\!\sqrt{(3)/(2)} - 1\right) R_E= 0.225(6.371×10^2\:\text{km})


\:\:\:\:\:= 1433\:\text{km}

User DFG
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