The line passes through the y-axis at point (0,4).
Explanation:
On a coordinate plane, line DF goes through points (-1,-3) and (2,3).
So, the slope of the line DF is \frac{- 3 - 3}{- 1 - 2} = 2
−1−2
−3−3
=2
Then the straight line which is parallel to DF will be given by
y = 2x + c.
Where, c is any constant and we have to evaluate it if this line passes through the point (-4,-4).
So, - 4 = 2(- 4) + c
⇒ c = 4
So, the straight line which is parallel to DF and passes through the point (-4,-4) is y = 2x + 4.
Now, putting x = 0, we get, y = 4.
Therefore, the line passes through the y-axis at point (0,4). (Answer)