Question

Assign courseStudent's name with Smith, age with 20, and ID with 9999. Use the print member function and a separate cout statement to output courseStudents's data. End with a newline. Sample output from the given program:

#include
#include
using namespace std;
class PersonData {
public:
void SetName(string userName) {
lastName = userName;
};
void SetAge(int numYears) {
ageYears = numYears;
};
// Other parts omitted
void PrintAll() {
cout << "Name: " << lastName;
cout << ", Age: " << ageYears;
};
private:
int ageYears;
string lastName;
};
class StudentData: public PersonData {
public:
void SetID(int studentId) {
idNum = studentId;
};
int GetID() {
return idNum;
};
private:
int idNum;
};
int main() {
StudentData courseStudent;
/* Your solution goes here */
return 0;
}

Answer 1

Replace /* Your solution goes here */

with the following:

courseStudent.SetName("Smith");

courseStudent.SetAge(20);

courseStudent.SetID(9999);

courseStudent.PrintAll();

cout <<courseStudent.GetID();

Step-by-step explanation:

From the given code segment, we have the following methods defined under the StudentData class;

SetName -> It receives name from the main

SetAge -> It receives age from the main

SetID --> It receives ID from the main and passes it to GetID method

printID --> Prints all the required output.

So, we have:

Pass name to setName

courseStudent.SetName("Smith");

Pass age to setAge

courseStudent.SetAge(20);

Pass ID to setID

courseStudent.SetID(9999);

Print all necessary outputs

courseStudent.PrintAll();

Manually print the student ID

cout <<courseStudent.GetID();