Final answer:
To solve for the width of a rectangle with a length to width ratio of 10:6 and a perimeter of 160 meters, we set up a proportion, simplify the equation, combine like terms, and solve for the width. The final calculation reveals that the width of the rectangle is 30 meters.
Step-by-step explanation:
To find the measure of the width of a rectangle when the ratio of the length to the width is 10:6 and the perimeter is 160 meters, we can set up two proportions based on the given ratios and the formula for the perimeter of a rectangle, which is P = 2l + 2w (where P is the perimeter, l is the length, and w is the width).
From the given ratio of the length to width 10:6, we can say that for every 10 units of length, there are 6 units of width. We can express this as length = (10/6) × width or equivalently, width = (6/10) × length.
Using the perimeter formula, we have 160 = 2×(10/6×width) + 2×width.
Let's solve for the width:
- Simplify the equation: 160 = (20/6×width) + 2width
- To combine like terms, we first need a common denominator, so we convert 2width to (12/6)width
- Now we have 160 = (20/6 + 12/6)width
- Combine the terms: 160 = (32/6)width
- Multiply both sides by (6/32) to solve for width: width = 160 × (6/32)
- Simplify: width = 30 meters
Therefore, the measure of the width of the rectangle is 30 meters.