Question

A bag contains white, red, and blue marble. If one marble is drawn randomly from a bag, not replaced, and a second marble is drawn, display all possible outcomes as an organized list.

Answer 1

The question involves listing the possible outcomes when drawing two marbles from a bag without replacement. Assuming there are initially four blue and three white marbles, the possible outcomes would be BB, BW, WB, and WW. The number and color of the marbles affect the probabilities on the second draw.

Step-by-step explanation:

To display all possible outcomes, we can create an organized list. It is important to note that after one marble is drawn and not replaced, the total number of marbles in the bag decreases, thus changing the probabilities of drawing each color on the second draw.
Assuming we have a bag with white, red, and blue marbles, and the situation presented in the information suggests different amounts of each color in various scenarios. For this explanation, let's assume we initially have four blue marbles and three white marbles (the red and other colors mentioned are irrelevant for our case).

If Maria draws one marble, sets it aside, and then draws a second marble, the possible outcomes for each draw can be listed as follows:

1. First Draw: Blue (B), White (W)
2. Second Draw (if the first was B): Blue (B), White (W)
3. Second Draw (if the first was W): Blue (B), White (W)

Therefore, the complete list of possible outcomes is:

1. BB - Blue then Blue
2. BW - Blue then White
3. WB - White then Blue
4. WW - White then White

Since the bag started with four blue and three white marbles, after drawing a blue marble, there will be three blue and three white marbles left. So, the probabilities of drawing each color change on the second draw.

If we were to include red marbles as well in the calculations, the list would expand to include combinations with red, but for the sake of this question, we are focusing on blue and white marbles only.