Question

How much energy is required to heat 14 grams of water from 18 degrees Celsius to 47 degrees Celsius

Answer 1

`Q=1,698.7J`

Step-by-step explanation:

Hello!

In this case, since the calculation of the required energy is performed via the following equation:

`Q=mC(T_f-T_i)`

Thus, since the mass is 14 g, specific heat is 4.184 J(g*°C) and the temperatures are 47 °C and 18 °C respectively, the resulting energy is:

`Q=14g*4.184(J)/(g\°C)(47°C-18°C)\\\\Q=1,698.7J`

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