Question

What is the weight in grams of 3.36 x 10^23 molecules of copper sulfate

Answer 1

`m=89.0g`

Step-by-step explanation:

Hello!

In this case, since we are given the formula units (molecules) of copper sulfate, it is possible to compute the moles of this compound via the Avogadro's number:

`n=3.36x10^(23)molecules*(1mol)/(6.022x10^(23)molecules)\\\\n=0.558mol`

Now, given the molar mass of copper sulfate which is 159.60 g/mol, the required mass in grams turns out:

`m=0.558mol*(159.60g)/(1mol)\\\\m=89.0g`

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