Question

An ice skater with a mass of 50 kg is gliding acrossthe ice at a speed of 8 m/s when herfriend comes up from behind and gives her a push,causing her speed to increase to 12m/s. How much work did the friend do on the skater

Answer 1

`W=2KJ`

Step-by-step explanation:

From the question we are told that:

Mass
`M=50kg`

Initial Velocity
`v_1=8m/s`

Final Velocity
`v_2=12m/s`

Generally the equation for Work-done is mathematically given by

W=\triangle K.E

Therefore

`W=0.5M(v_2^2-v_1^2)`

`W=0.5*50(12^2-8^2)`

`W=2KJ`