Question

A) What mass in grams of H20 is needed to react completely with 40.0 g of

Na2O2?

M(H2O) =18.02g/mol
M(NA2O2)= 78g/mol


Ecuation:

2Na2O2 (s)+2h2O(I)—> 4NaOH(aq) + O2 (g)

Answer 1

`m_(H_2O)=9.24gH_2O`

Step-by-step explanation:

Hello there!

In this case, since there is a 2:2 mole ratio between sodium peroxide and water according to the given reaction, it is possible to apply the following stoichiometric setup for the calculation of the required mass of water:

`m_(H_2O)=40.0gNa_O_2*(1molNa_O_2)/(78gNa_O_2)*(2molH_2O)/(2molNa_O_2) *(18.02gH_2O)/(1molH_2O) \\\\m_(H_2O)=9.24gH_2O`

Best regards!