Question

Help please I have no clue what im doing.

Answer 1

x = 10

`m\angle DCE=55\degree`

Explanation:

Since, CE bisects angle DCF, therefore:

`m\angle ECF= m\angle DCE`

`6x-5=4x + 15`

`6x-4x=5 + 15`

`2x=20`

`x=(20)/(2)`

`x=10`

`m\angle DCE=(4x+15)\degree`

`m\angle DCE=(4* 10+15)\degree`

`m\angle DCE=(40+15)\degree`

`m\angle DCE=55\degree`