Question

How do I solve this question?​

Answer 1

`-7 (1)/(2)`

Explanation:

`\frac{6 {x}^( - 1) {y}^{ (7)/(2) } }{ \sqrt{16 {x}^(2) } {y}^(2) } \\ \\ = \frac{6 {x}^( - 1) {y}^{ (7)/(2) } }{ \sqrt{(4 {x} {y})^(2) }}\\ \\ = \frac{6 {x}^( - 1) {y}^{ (7)/(2) } }{ {4 {x} {y}}}\\ \\ = (6)/(4) {x }^( - 1 - 1) {y}^{ (7)/(2) - 1 } \\ \\ = (3)/(2) {x }^( - 2) {y}^{ (5)/(2) } \\ \\ equating \: it \: with \: \\ a {x}^(b) {y}^(c) \\ \\ \implies \\ a = (3)/(2) \\ \\ b = - 2 \\ \\ c = (5)/(2) \\ \\ abc = (3)/(2) * ( - 2) * (5)/(2) \\ \\ = - (15)/(2) \\ \\ =- 7 (1)/(2) \\`