Question

A straight wire in a magnetic field experiences a force of 0.026 N when the current in the wire is 1.5 A. The current in the wire is changed, and the wire experiences a force of 0.063 N as a result. What is the new current

Answer 1

the new current on the wire is 3.64 A.

Step-by-step explanation:

Given;

first force on the wire, F₁ = 0.026 N

second force on the wire, F₂ = 0.063 N

first current on the wire, I₁ = 1.5 A

second current on the wire, I₂ = ?

The force on a current carrying conductor placed in a magnetic field is given as;

`F = BIL(sin \theta)\\\\`

F ∝ I

`(F_1)/(I_1) = (F_2)/(I_2) \\\\I_2 = (F_2I_1)/(F_1) \\\\I_2 = (0.063\ *\ 1.5 )/(0.026) \\\\I_2 = 3.64 \ A`

Therefore, the new current on the wire is 3.64 A.