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What is the equation of the parabola that has a vertex at (3,1) and passes through point (2,-1)? Explain the answer

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Answer:

Explanation:

Down-opening parabola with vertex (3,1):

y = a(x-3)^2+1

(2,-1) is a point on the parabola.

-1 = a(2-3)^2 +1

a = -2

y = -2(x/3)^2 + 1

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