Question

An amoeba has 1.00 x 1016 protons and a net charge of 0.300 pC. Assuming there are 1.88 x 106 fewer electrons than protons, If you paired them up, what fraction of the protons would have no electrons

Answer 1

The fraction of the protons would have no electrons
`=1.88* 10^(-10)`

Step-by-step explanation:

We are given that

Amoeba has total number of protons=
`1.00* 10^(16)`

Net charge, Q=0.300pC

Electrons are fewer than protons=
`1.88* 10^6`

We have to find the fraction of protons would have no electrons.

The fraction of the protons would have no electrons

=
`(Fewer\;electrons)/(Total\;protons)`

The fraction of the protons would have no electrons

=
`(1.88* 10^(6))/(1.00* 10^(16))`

`=1.88* 10^(-10)`

Hence, the fraction of the protons would have no electrons
`=1.88* 10^(-10)`