Question

Using law of sines please show process and answer

Answer 1

Hello,

`\widehat{A}=180^o-24.4^o-103.6^o=52^o\\\\(sin(24.4^o))/(37.3) =(sin(103.6^o))/(c) \\\\\\c=87.760246\approx{87.8}\\\\\\(sin(52^o))/(a) =(sin(24.4^o))/(37.3) \\\\\\a=71.1510189...\approx{71.2}\\`