Question

IM TIMED HALP!!!

Relationship A and Relationship B show the change in the temperature for a pot of water on the stove. Relationship B has a greater rate than Relationship A.

This table represents Relationship A.

Time (min) 2 3 7 9
Temperature (°C) 61.3 64.9 79.3 86.5
What table could represent Relationship B?


Time (min) 2 3 7 9
Temperature (°C) 61.0 64.6 79.0 86.2

Time (min) 2 3 7 9
Temperature (°C) 60.6 64.3 79.1 86.5

Time (min) 2 3 7 9
Temperature (°C) 61.0 64.4 78.0 84.8

Time (min) 2 3 7 9
Temperature (°C) 61.8 65.3 79.3 86.3

Answer 1

The table representing Relationship B is option 2

`\begin{array}{ccc}Time \ (min)&&Temperature \ (^(\circ)C)\\2&&60.6\\3&&64.3\\7&&79.1\\9&&86.5\end{array}`

Explanation:

The relationship shown by Relationship A and Relationship B = The change in the temperature for a pot of water om the stove

The rate of Relationship B > The rate of Relationship A

The table for relationship A is given as follows';

`\begin{array}{ccc}Time \ (min)&&Temperature \ (^(\circ)C)\\2&&61.3\\3&&64.9\\7&&79.3\\9&&86.5\end{array}`

The time in minutes are the x-values, while the temperature in °C Ere the y-values

The rate for Relationship A,
`m_A` = (86.5 - 61.3)/(9 - 2) = 3.6

Therefore, the rate for Relationship B > 3.6

By checking each option, we note that in option 2, the maximum value for the y-value is the same as for Relationship A, which is 86.5°C, while the minimum value for the time, t, is lesser than that for Relationship A, (60.6 minutes < 61.3 minutes) therefore, we get;

The rate for option 2 = (86.5 - 60.6)/(9 - 2) = 3.7

Therefore, the table that represents the Relationship B is the table for option 2

`\begin{array}{ccc}Time \ (min)&&Temperature \ (^(\circ)C)\\2&&60.6\\3&&64.3\\7&&79.1\\9&&86.5\end{array}`